27^5x=(1/9)^2x-1

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Solution for 27^5x=(1/9)^2x-1 equation: 



27^5x=(1/9)^2x-1

We move all terms to the left:

27^5x-((1/9)^2x-1)=0



Domain of the equation: 9)^2x-1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

27^5x-((+1/9)^2x-1)=0

We multiply all the terms by the denominator


27^5x*9)^2x-1)-((+1=0

Wy multiply elements

243x^6+1=0

We do not support expression: x^6

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